HOME | DD
emperpep β chromacolour : Rosa
#pokemon #rosa #emperpep #chromacolour
Published: 2016-12-02 10:39:00 +0000 UTC; Views: 29873; Favourites: 1153; Downloads: 136
Redirect to original
Description
Rosa from Pokemon
Chromacolour on 100g sketchbook paperΒ
if you have any question, feel free to ask
Related content
Comments: 45
π: 0 β©: 0
It must have spent a lot of time.As a high school student,I don't think if I can draw such an amazing art!
π: 0 β©: 0
JHDKJGJSDFHGHSDFKGHKSHDFKHGKHSDKHGFJHGSHDFH WHOAAAAA SO CUTEEEEEEEEE
π: 0 β©: 0
So prettyyyy! >w<
I'm not familiar with the medium you said you used, but the results look pretty similar to your watercoloring. So nice! *__*
π: 0 β©: 1
Thank you , chromacolour is like matte acrylic [waterproof once dry], but feel somewhat smoother than normal acrylic
π: 0 β©: 1
That actually sounds interesting! I have to look them up now and see how much they'd cost! *__*
Thanks Pep!
π: 0 β©: 0
I have questions actually:
Is chromacolour like watercolors?Β
And if you know, what's the difference between colored pencils and polychromos?
Thanks!
π: 0 β©: 1
chromacolour is more like matte opaque acrylic+gouache , also waterproof once dry
and polychromos is artist grade colored pencil, they are oil based, lightfast, and have good color saturation compared to student grade colored pencil.
π: 0 β©: 0
no is a anime xD
it's pokemon!!!
π: 0 β©: 1
Oh wow! Thanks for telling me!!!!
π: 0 β©: 0
So cute!
How long did it take you to get this good?
π: 0 β©: 1
I've been drawing since 2004
π: 0 β©: 2
i really your work!! but i have a question for you
how you made the Β skin color? :c
for my is really dificcult to make this color
π: 0 β©: 1
I usually used orange, if it is watercolor I will add more water to make it lighter, if it is acrylic or gouache I will add white to turn it into light color
π: 0 β©: 1
ohhh!! >w<
thanks you very much emperpep-sama!!
i really love your art Β :3
π: 0 β©: 0
Nice job working on this^^ Most impressive!
π: 0 β©: 0
Thats very pretty
Im not a rosa fan but this is very cute
π: 0 β©: 0
